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1.5x^2-0.16=0.08
We move all terms to the left:
1.5x^2-0.16-(0.08)=0
We add all the numbers together, and all the variables
1.5x^2-0.24=0
a = 1.5; b = 0; c = -0.24;
Δ = b2-4ac
Δ = 02-4·1.5·(-0.24)
Δ = 1.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{1.44}}{2*1.5}=\frac{0-\sqrt{1.44}}{3} =-\frac{\sqrt{}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{1.44}}{2*1.5}=\frac{0+\sqrt{1.44}}{3} =\frac{\sqrt{}}{3} $
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